Integrand size = 35, antiderivative size = 503 \[ \int (f x)^m (\text {d1}+c \text {d1} x)^{3/2} (\text {d2}-c \text {d2} x)^{3/2} (a+b \text {arccosh}(c x)) \, dx=-\frac {3 b c \text {d1} \text {d2} (f x)^{2+m} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x}}{f^2 (2+m)^2 (4+m) \sqrt {-1+c x} \sqrt {1+c x}}-\frac {b c \text {d1} \text {d2} (f x)^{2+m} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x}}{f^2 (2+m) (4+m) \sqrt {-1+c x} \sqrt {1+c x}}+\frac {b c^3 \text {d1} \text {d2} (f x)^{4+m} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x}}{f^4 (4+m)^2 \sqrt {-1+c x} \sqrt {1+c x}}+\frac {3 \text {d1} \text {d2} (f x)^{1+m} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x} (a+b \text {arccosh}(c x))}{f \left (8+6 m+m^2\right )}+\frac {(f x)^{1+m} (\text {d1}+c \text {d1} x)^{3/2} (\text {d2}-c \text {d2} x)^{3/2} (a+b \text {arccosh}(c x))}{f (4+m)}+\frac {3 \text {d1} \text {d2} (f x)^{1+m} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x} (a+b \text {arccosh}(c x)) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1+m}{2},\frac {3+m}{2},c^2 x^2\right )}{f (4+m) \left (2+3 m+m^2\right ) \sqrt {1-c x} \sqrt {1+c x}}-\frac {3 b c \text {d1} \text {d2} (f x)^{2+m} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x} \, _3F_2\left (1,1+\frac {m}{2},1+\frac {m}{2};\frac {3}{2}+\frac {m}{2},2+\frac {m}{2};c^2 x^2\right )}{f^2 (1+m) (2+m)^2 (4+m) \sqrt {-1+c x} \sqrt {1+c x}} \]
[Out]
Time = 0.66 (sec) , antiderivative size = 503, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.171, Rules used = {5931, 5927, 5949, 32, 74, 14} \[ \int (f x)^m (\text {d1}+c \text {d1} x)^{3/2} (\text {d2}-c \text {d2} x)^{3/2} (a+b \text {arccosh}(c x)) \, dx=-\frac {3 b c \text {d1} \text {d2} \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x} (f x)^{m+2} \, _3F_2\left (1,\frac {m}{2}+1,\frac {m}{2}+1;\frac {m}{2}+\frac {3}{2},\frac {m}{2}+2;c^2 x^2\right )}{f^2 (m+1) (m+2)^2 (m+4) \sqrt {c x-1} \sqrt {c x+1}}+\frac {3 \text {d1} \text {d2} \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x} (f x)^{m+1} \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {m+1}{2},\frac {m+3}{2},c^2 x^2\right ) (a+b \text {arccosh}(c x))}{f (m+4) \left (m^2+3 m+2\right ) \sqrt {1-c x} \sqrt {c x+1}}+\frac {3 \text {d1} \text {d2} \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x} (f x)^{m+1} (a+b \text {arccosh}(c x))}{f \left (m^2+6 m+8\right )}+\frac {(c \text {d1} x+\text {d1})^{3/2} (\text {d2}-c \text {d2} x)^{3/2} (f x)^{m+1} (a+b \text {arccosh}(c x))}{f (m+4)}+\frac {b c^3 \text {d1} \text {d2} \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x} (f x)^{m+4}}{f^4 (m+4)^2 \sqrt {c x-1} \sqrt {c x+1}}-\frac {b c \text {d1} \text {d2} \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x} (f x)^{m+2}}{f^2 (m+2) (m+4) \sqrt {c x-1} \sqrt {c x+1}}-\frac {3 b c \text {d1} \text {d2} \sqrt {c \text {d1} x+\text {d1}} \sqrt {\text {d2}-c \text {d2} x} (f x)^{m+2}}{f^2 (m+2)^2 (m+4) \sqrt {c x-1} \sqrt {c x+1}} \]
[In]
[Out]
Rule 14
Rule 32
Rule 74
Rule 5927
Rule 5931
Rule 5949
Rubi steps \begin{align*} \text {integral}& = \frac {(f x)^{1+m} (\text {d1}+c \text {d1} x)^{3/2} (\text {d2}-c \text {d2} x)^{3/2} (a+b \text {arccosh}(c x))}{f (4+m)}+\frac {(3 \text {d1} \text {d2}) \int (f x)^m \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x} (a+b \text {arccosh}(c x)) \, dx}{4+m}+\frac {\left (b c \text {d1} \text {d2} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x}\right ) \int (f x)^{1+m} (-1+c x) (1+c x) \, dx}{f (4+m) \sqrt {-1+c x} \sqrt {1+c x}} \\ & = \frac {3 \text {d1} \text {d2} (f x)^{1+m} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x} (a+b \text {arccosh}(c x))}{f \left (8+6 m+m^2\right )}+\frac {(f x)^{1+m} (\text {d1}+c \text {d1} x)^{3/2} (\text {d2}-c \text {d2} x)^{3/2} (a+b \text {arccosh}(c x))}{f (4+m)}+\frac {\left (b c \text {d1} \text {d2} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x}\right ) \int (f x)^{1+m} \left (-1+c^2 x^2\right ) \, dx}{f (4+m) \sqrt {-1+c x} \sqrt {1+c x}}-\frac {\left (3 \text {d1} \text {d2} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x}\right ) \int \frac {(f x)^m (a+b \text {arccosh}(c x))}{\sqrt {-1+c x} \sqrt {1+c x}} \, dx}{(2+m) (4+m) \sqrt {-1+c x} \sqrt {1+c x}}-\frac {\left (3 b c \text {d1} \text {d2} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x}\right ) \int (f x)^{1+m} \, dx}{f (2+m) (4+m) \sqrt {-1+c x} \sqrt {1+c x}} \\ & = -\frac {3 b c \text {d1} \text {d2} (f x)^{2+m} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x}}{f^2 (2+m)^2 (4+m) \sqrt {-1+c x} \sqrt {1+c x}}+\frac {3 \text {d1} \text {d2} (f x)^{1+m} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x} (a+b \text {arccosh}(c x))}{f \left (8+6 m+m^2\right )}+\frac {(f x)^{1+m} (\text {d1}+c \text {d1} x)^{3/2} (\text {d2}-c \text {d2} x)^{3/2} (a+b \text {arccosh}(c x))}{f (4+m)}+\frac {3 \text {d1} \text {d2} (f x)^{1+m} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x} (a+b \text {arccosh}(c x)) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1+m}{2},\frac {3+m}{2},c^2 x^2\right )}{f (1+m) (2+m) (4+m) \sqrt {1-c x} \sqrt {1+c x}}-\frac {3 b c \text {d1} \text {d2} (f x)^{2+m} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x} \, _3F_2\left (1,1+\frac {m}{2},1+\frac {m}{2};\frac {3}{2}+\frac {m}{2},2+\frac {m}{2};c^2 x^2\right )}{f^2 (1+m) (2+m)^2 (4+m) \sqrt {-1+c x} \sqrt {1+c x}}+\frac {\left (b c \text {d1} \text {d2} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x}\right ) \int \left (-(f x)^{1+m}+\frac {c^2 (f x)^{3+m}}{f^2}\right ) \, dx}{f (4+m) \sqrt {-1+c x} \sqrt {1+c x}} \\ & = -\frac {3 b c \text {d1} \text {d2} (f x)^{2+m} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x}}{f^2 (2+m)^2 (4+m) \sqrt {-1+c x} \sqrt {1+c x}}-\frac {b c \text {d1} \text {d2} (f x)^{2+m} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x}}{f^2 (2+m) (4+m) \sqrt {-1+c x} \sqrt {1+c x}}+\frac {b c^3 \text {d1} \text {d2} (f x)^{4+m} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x}}{f^4 (4+m)^2 \sqrt {-1+c x} \sqrt {1+c x}}+\frac {3 \text {d1} \text {d2} (f x)^{1+m} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x} (a+b \text {arccosh}(c x))}{f \left (8+6 m+m^2\right )}+\frac {(f x)^{1+m} (\text {d1}+c \text {d1} x)^{3/2} (\text {d2}-c \text {d2} x)^{3/2} (a+b \text {arccosh}(c x))}{f (4+m)}+\frac {3 \text {d1} \text {d2} (f x)^{1+m} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x} (a+b \text {arccosh}(c x)) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1+m}{2},\frac {3+m}{2},c^2 x^2\right )}{f (1+m) (2+m) (4+m) \sqrt {1-c x} \sqrt {1+c x}}-\frac {3 b c \text {d1} \text {d2} (f x)^{2+m} \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x} \, _3F_2\left (1,1+\frac {m}{2},1+\frac {m}{2};\frac {3}{2}+\frac {m}{2},2+\frac {m}{2};c^2 x^2\right )}{f^2 (1+m) (2+m)^2 (4+m) \sqrt {-1+c x} \sqrt {1+c x}} \\ \end{align*}
Time = 0.76 (sec) , antiderivative size = 288, normalized size of antiderivative = 0.57 \[ \int (f x)^m (\text {d1}+c \text {d1} x)^{3/2} (\text {d2}-c \text {d2} x)^{3/2} (a+b \text {arccosh}(c x)) \, dx=\frac {\text {d1} \text {d2} x (f x)^m \sqrt {\text {d1}+c \text {d1} x} \sqrt {\text {d2}-c \text {d2} x} \left (-\frac {3 b c x}{(2+m)^2 \sqrt {-1+c x} \sqrt {1+c x}}+\frac {b c x \left (-\frac {1}{2+m}+\frac {c^2 x^2}{4+m}\right )}{\sqrt {-1+c x} \sqrt {1+c x}}+\frac {3 (a+b \text {arccosh}(c x))}{2+m}-(-1+c x) (1+c x) (a+b \text {arccosh}(c x))-\frac {3 \sqrt {1-c^2 x^2} (a+b \text {arccosh}(c x)) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1+m}{2},\frac {3+m}{2},c^2 x^2\right )}{(1+m) (2+m) (-1+c x) (1+c x)}-\frac {3 b c x \, _3F_2\left (1,1+\frac {m}{2},1+\frac {m}{2};\frac {3}{2}+\frac {m}{2},2+\frac {m}{2};c^2 x^2\right )}{(1+m) (2+m)^2 \sqrt {-1+c x} \sqrt {1+c x}}\right )}{4+m} \]
[In]
[Out]
\[\int \left (f x \right )^{m} \left (c \operatorname {d1} x +\operatorname {d1} \right )^{\frac {3}{2}} \left (-c \operatorname {d2} x +\operatorname {d2} \right )^{\frac {3}{2}} \left (a +b \,\operatorname {arccosh}\left (c x \right )\right )d x\]
[In]
[Out]
\[ \int (f x)^m (\text {d1}+c \text {d1} x)^{3/2} (\text {d2}-c \text {d2} x)^{3/2} (a+b \text {arccosh}(c x)) \, dx=\int { {\left (c d_{1} x + d_{1}\right )}^{\frac {3}{2}} {\left (-c d_{2} x + d_{2}\right )}^{\frac {3}{2}} {\left (b \operatorname {arcosh}\left (c x\right ) + a\right )} \left (f x\right )^{m} \,d x } \]
[In]
[Out]
Timed out. \[ \int (f x)^m (\text {d1}+c \text {d1} x)^{3/2} (\text {d2}-c \text {d2} x)^{3/2} (a+b \text {arccosh}(c x)) \, dx=\text {Timed out} \]
[In]
[Out]
\[ \int (f x)^m (\text {d1}+c \text {d1} x)^{3/2} (\text {d2}-c \text {d2} x)^{3/2} (a+b \text {arccosh}(c x)) \, dx=\int { {\left (c d_{1} x + d_{1}\right )}^{\frac {3}{2}} {\left (-c d_{2} x + d_{2}\right )}^{\frac {3}{2}} {\left (b \operatorname {arcosh}\left (c x\right ) + a\right )} \left (f x\right )^{m} \,d x } \]
[In]
[Out]
\[ \int (f x)^m (\text {d1}+c \text {d1} x)^{3/2} (\text {d2}-c \text {d2} x)^{3/2} (a+b \text {arccosh}(c x)) \, dx=\int { {\left (c d_{1} x + d_{1}\right )}^{\frac {3}{2}} {\left (-c d_{2} x + d_{2}\right )}^{\frac {3}{2}} {\left (b \operatorname {arcosh}\left (c x\right ) + a\right )} \left (f x\right )^{m} \,d x } \]
[In]
[Out]
Timed out. \[ \int (f x)^m (\text {d1}+c \text {d1} x)^{3/2} (\text {d2}-c \text {d2} x)^{3/2} (a+b \text {arccosh}(c x)) \, dx=\int \left (a+b\,\mathrm {acosh}\left (c\,x\right )\right )\,{\left (f\,x\right )}^m\,{\left (d_{1}+c\,d_{1}\,x\right )}^{3/2}\,{\left (d_{2}-c\,d_{2}\,x\right )}^{3/2} \,d x \]
[In]
[Out]